| Summary: | Exclude changed words in track-changes from "replace all" operations. | ||
|---|---|---|---|
| Product: | LibreOffice | Reporter: | Hussam Al-Tayeb <ht990332> |
| Component: | Writer | Assignee: | Not Assigned <libreoffice-bugs> |
| Status: | RESOLVED DUPLICATE | ||
| Severity: | normal | CC: | ming.v.hua |
| Priority: | medium | ||
| Version: | 6.4.0.0.beta1+ | ||
| Hardware: | x86-64 (AMD64) | ||
| OS: | Linux (All) | ||
| Whiteboard: | |||
| Crash report or crash signature: | Regression By: | ||
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Description
Hussam Al-Tayeb
2019-11-23 15:59:16 UTC
I can reproduce the reported behavior in 6.2.8, but only if Edit -> Track Changes -> Show (or View -> Track Changes) is turned on. Version: 6.2.8.2 (x64) Build ID: f82ddfca21ebc1e222a662a32b25c0c9d20169ee CPU threads: 2; OS: Windows 10.0; UI render: default; VCL: win; Locale: zh-CN (zh_CN); UI-Language: en-US Calc: threaded I'm not sure it's a bug, though. At least for "Find" to find tracked deletion seems reasonable. Try a docx file (NOT odt). It happens there even if I do not enable view -> "Track changes". It is definitely a bug though. Why would anyone want to return deleted words as result? (In reply to Hussam Al-Tayeb from comment #2) > Try a docx file (NOT odt). It happens there even if I do not enable view -> > "Track changes". > > It is definitely a bug though. Why would anyone want to return deleted words > as result? And even be able to replace deleted words by more deleted words creating an infinite loop on 'replace all'? Please search before reporting. This seems like duplicate of https://bugs.documentfoundation.org/show_bug.cgi?id=36582. If not, please explain. *** This bug has been marked as a duplicate of bug 36582 *** (In reply to Timur from comment #4) > Please search before reporting. > This seems like duplicate of > https://bugs.documentfoundation.org/show_bug.cgi?id=36582. > If not, please explain. > > *** This bug has been marked as a duplicate of bug 36582 *** Thank you! |