Bug 150185 - Error while working with an array of structures.
Summary: Error while working with an array of structures.
Status: NEW
Alias: None
Product: LibreOffice
Classification: Unclassified
Component: BASIC (show other bugs)
Version:
(earliest affected)
Inherited From OOo
Hardware: All All
: medium normal
Assignee: Not Assigned
URL:
Whiteboard:
Keywords:
Depends on:
Blocks:
 
Reported: 2022-07-28 12:18 UTC by Vladimir Sokolinskiy
Modified: 2024-07-28 03:15 UTC (History)
5 users (show)

See Also:
Crash report or crash signature:


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Description Vladimir Sokolinskiy 2022-07-28 12:18:34 UTC
Run macro:

Sub TestAWTPoint
  Dim p(0) As New com.sun.star.awt.Point
  Dim h As New com.sun.star.awt.Point
  h.X=1
  p(0)=h
  Msgbox "h.X=" & h.X & " p(0).X=" & p(0).X 
End Sub

Result:  h.X=1 p(0).X=0
Must be: h.X=1 p(0).X=1

Looks like an error in the interpretation of the expression p(0).X
Comment 1 Mike Kaganski 2022-07-28 13:36:45 UTC
Repro.
Comment 2 Mike Kaganski 2022-07-28 13:38:43 UTC
Note that the following works OK:

Sub TestAWTPointInVAriantArray
  Dim p(0)
  Dim h As New com.sun.star.awt.Point
  h.X=1
  p(0)=h
  Msgbox "h.X=" & h.X & " p(0).X=" & p(0).X 
End Sub
Comment 3 Rafael Lima 2022-07-28 14:08:18 UTC
As pointed out by Mike, using Object or Variant as the type of p(0) will work.

Sub Test1
  Dim p(0) As Object
  Dim h As New com.sun.star.awt.Point
  h.X=1
  p(0)=h
  Msgbox "h.X=" & h.X & " p(0).X=" & p(0).X 
End Sub

Now one thing bent my mind. Although printing p(0).X returns 0, if you inspect p(0) using XRay Tool you'll see that X = 1 inside p(0). What gives?

Sub Test2
  Dim p(0) As New com.sun.star.awt.Point
  Dim h As New com.sun.star.awt.Point
  h.x = 1
  p(0) = h
  MsgBox p(0).X ' Prints 0
  XRay p(0) ' Here p(0).X is equal to 1
End Sub
Comment 4 Vladimir Sokolinskiy 2022-07-28 14:30:06 UTC
The built-in debugger in the IDE also sees no problem with the p array from the start message.

The problem arises for arrays of structures. Same for custom types:

Type MyType 
  X As Long
End Type  

Sub TestCustomType
  Dim p(0) As MyType
  Dim h As MyType
  h.X=1
  p(0)=h
  Msgbox "h.X=" & h.X & " p(0).X=" & p(0).X 
End Sub

Result: h.X=1 p(0).X=0
Comment 5 Vladimir Sokolinskiy 2022-07-28 17:19:35 UTC
The array elements are correct in all examples. The construct p(0).X "sees" the previous version of p(0).

Sub TestAWTPoint5
  Dim p(0) As New com.sun.star.awt.Point, q
  Dim h As New com.sun.star.awt.Point
  Dim v
  p(0).X=9
  h.X=1
  p(0)=h
  Msgbox "h.X=" & h.X & " p(0).X=" & p(0).X   ' h.X=1 p(0).X=9
  v=p(0)
  Msgbox "v.X=" & v.X                         ' v.X=1  
End Sub
Comment 6 QA Administrators 2024-07-28 03:15:14 UTC
Dear Vladimir Sokolinskiy,

To make sure we're focusing on the bugs that affect our users today, LibreOffice QA is asking bug reporters and confirmers to retest open, confirmed bugs which have not been touched for over a year.

There have been thousands of bug fixes and commits since anyone checked on this bug report. During that time, it's possible that the bug has been fixed, or the details of the problem have changed. We'd really appreciate your help in getting confirmation that the bug is still present.

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